2x^2-x+20=100

Solution for 2x^2-x+20=100 equation:

2x^2-x+20=100

We move all terms to the left:

2x^2-x+20-(100)=0

We add all the numbers together, and all the variables

2x^2-1x-80=0

a = 2; b = -1; c = -80;
Δ = b2-4ac
Δ = -12-4·2·(-80)
Δ = 641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{641}}{2*2}=\frac{1-\sqrt{641}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{641}}{2*2}=\frac{1+\sqrt{641}}{4}
$